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Thanks. I (obviously) agree. The only problem is that it's not always computationally easy to optimize the thing you really care about.
by danger 16y ago
Thanks. I (obviously) agree. The only problem is that it's not always computationally easy to optimize the thing you really care about.
- bumticks 16y agoTotally. It often becomes a trade-off of doing an alright job, e.g. approximately, optimizing the loss you're really interested in vs. doing a great job optimizing a tangentially related but much less appropriate loss.