3 ms·
> max_seq_no = max_acked_seq_no + window_size What about the packets below max_acked_seq_no which haven't been ACKed? Shouldn't the total number of those be su
by jancsika 7y ago
> max_seq_no = max_acked_seq_no + window_size
What about the packets below max_acked_seq_no which haven't been ACKed? Shouldn't the total number of those be subtracted from the sum above?