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0.9999 = 1 is a consequence of the way we define rational and real numbers and limits. There are alternative definitions of numbers where this equality does not
by heinrichhartman 6y ago
0.9999 = 1 is a consequence of the way we define rational and real numbers and limits. There are alternative definitions of numbers where this equality does not hold:
Non Standard Analysis https://en.wikipedia.org/wiki/Nonstandard_analysis https://en.wikipedia.org/wiki/Nonstandard_analysis being the most famous one.
But for the sake of argument, let's just define numbers as sequences of digits with a mixed in period somewhere:
MyNumber := {
a = (a_1, a_2, ...) -- list of digits a_i = 0 .. 9; a_1 != 0.
e -- exponent (integer)
s -- sign (+/- 1)
}
Each such sequence corresponds to the (classical) real number: s * \sum_i a_i * 10^{i + e}.
We can go on and define addition, subtraction, multiplication and division in the familiar way.
Problems arise only when we try to establish desireable properties, e.g.
(1/3) * 3 = 1
Does NOT hold here, since 0.9999... is a difference sequence than 1.000....
So yes, you can define these number systems, and you will have 0.999... != 1.
But working with them will be pretty awkward, since a lot of familiar arithmetic breaks down.
- astrobe_ 6y ago1 = 0.9... is the consequence of purposely ambiguous and questionable notation. That's an old teachers' trick to make students talk and listen about mathematics.
- heinrichhartman 6y agoThis has nothing to do with notation. It's perfectly possible to define infinite sequences without using dots. In particular if they are constant. In the above case: a_i = 9 for i \in \IZ and i < 0 a_i = 0 for i \in \IZ and i >= 0 Where \IZ are the integers.