3 ms·
Okay so something like: probability of spreading = a * n probability of infected = b * n where: a,b = some blackbox function for spreading/infection ratio?
by saeranv 6y ago
Okay so something like:
probability of spreading = a * n
probability of infected = b * n
where:
a,b = some blackbox function for spreading/infection ratio?
n = number of people you meet
Assuming both are independent events we get:
p = a * b * n^2
I can see how we get n^2 with that. The way I'm using a, and b seems clumsy though, is there a better way?
- scythe 6y agoIn math and (especially) physics it is common to express "proportionality" laws usually with a symbol that looks like LaTeX \propto. So for instance the activity A of a radioactive sample is written A \propto e^(-t/T) where t is time and T is the mean lifetime of a single particle. For convenience \propto is often transliterated as ~ when typing. So that becomes p_catch ~ n p_spread ~ n p_relay = p_spread * p_catch ~ n^2.
- saeranv 6y agoThanks, that's a much clearer way to think of it.