4 ms·
log (x) is approximated by √x iterated n times x^(0.5^n), multiplied by a constant equal to (2^n + [fudge factor for √'s finite precision]) The best answer is
by lonelappde 7y ago
log (x) is approximated by
√x iterated n times x^(0.5^n), multiplied by a constant equal to (2^n + [fudge factor for √'s finite precision])
The best answer is a link to
https://m.imgur.com/s9eBx5Z https://m.imgur.com/s9eBx5Z
which solves the problem in math notation.
There's another comment that describes that in words, and a bunch of reddit chitchat.