3 ms·
The correct answer is, it’s complicated. (Of course) It depends greatly on the definition of the output, for example, which can vary by application. Easy answe
by esmi 7y ago
The correct answer is, it’s complicated. (Of course) It depends greatly on the definition of the output, for example, which can vary by application.
Easy answer is, for a fixed load (I.e. a resistor) and frequency, one varies amplitude with power. (perhaps absolute value of area under the curve might be a better description)
For more information see here:
http://hyperphysics.phy-astr.gsu.edu/hbase/Waves/powstr.html http://hyperphysics.phy-astr.gsu.edu/hbase/Waves/powstr.html
This is for a physical string, which I think is easier to wrap your head around. The math is very similar for electrical waves.