4 ms·
Actually g(x) = 3 is multiplicatively and additively invertible.
Actually g(x) = 3 is multiplicatively and additively invertible.
g(x) = 3, alone, is not. I give you 3, and there's no possible way you're telling me what the original x value was. f(x) = x ⋄ g(x) is (for ⋄ in {+, ×}), but that's a different matter entirely.
If I pick an x and tell you that g(x) = 3 can you tell me what x is?