3 ms·
>Ψ(x,t) = phi(t)ψ(x) = Ae^(−Et/ℏ)ψ(x) This equation is missing a sum symbol, also it should be e^(-iEt/ℏ), where in the correct case the amplitude does not cha
by scythe 7y ago
>Ψ(x,t) = phi(t)ψ(x) = Ae^(−Et/ℏ)ψ(x)
This equation is missing a sum symbol, also it should be e^(-iEt/ℏ), where in the correct case the amplitude does not change. What you get is a sum of products of each occupied stationary state and a time-dependent phase. So the general solution looks like this:
https://en.wikipedia.org/w/index.php?title=User:Scythe33/sandbox&oldid=948716529 https://en.wikipedia.org/w/index.php?title=User:Scythe33/san...
- monktastic1 7y agoIndeed. But as another commenter points out, what I think they wanted was to solve only for eigenstates here. Apparently I'm not the only one this confused.