2 ms·
Isn't it going to short-circuit with the return of the first truthy statement?
by XCSme 7y ago
Isn't it going to short-circuit with the return of the first truthy statement?
- foldr 7y agoThe expression immediately to the right of each 'case' keyword is evaluated before the resulting values are compared to true.
- deleted 7y ago[deleted]
- richgieg 7y agoIf that's the case, then wouldn't both "asdf" and "qwer" be printed to the console when executing the following code? function test() { switch (true) { case console.log('asdf') === undefined: return 1; case console.log('qwer') === undefined: return 2; } } test();
- foldr 7y agoHmm, I wrote some similar test code before writing my comment, but only included one 'case'. Indeed, you're right, they're evaluated only as needed.