3 ms·
> [reading memory} always will behave precisely and consistently What is the point of not making it UB? You can't AFAICS possibly rely on any useful way on it
by throwaway_pdp09 7y ago
> [reading memory} always will behave precisely and consistently
What is the point of not making it UB? You can't AFAICS possibly rely on any useful way on it behaving 'precisely and consistently' so just make it UB anyway?
- saagarjha 7y agoI think this lets you copy it around, e.g. when you have a struct that you have partially initialized.
- throwaway_pdp09 7y agoThat makes sense, finally. Thanks.