4 ms·
The famous Euler's identity e^(i * π) = -1, where i is the imaginary unit would not in fact hold if we changed the definition of the radian. It's just the mat
by vesinisa 7y ago
The famous Euler's identity
e^(i * π) = -1, where i is the imaginary unit
would not in fact hold if we changed the definition of the radian. It's just the mathematically natural way of expressing arguments to trigonometric functions.
- niklasbuschmann 7y agoI think Euler’s identity becomes more elegant when using 2π instead of π: e^(2πi) = 1
- epage 7y agoThe form I was taught: e^jpi + 1 = 0 The reason for this form is that it doesn't just contain an imaginary unit and the two most popular constants but the additive and multiplicative identities.