2 ms·
It requires a little bit of indirection. You'll find that you could easily solve the equation if you only knew one more quantity. So call the unknown "X" and ke
by tel 16y ago
It requires a little bit of indirection. You'll find that you could easily solve the equation if you only knew one more quantity. So call the unknown "X" and keep going. You'll be able to form an equation that constrains X to a single value.
FWIW, the answer I get has three non-zero decimal digits.