2 ms·
As far as I understand, we are talking about flux - per area at specified distance, not luminosity. I did recalculate flux for 0.5 m.
by blackhaz 7y ago
As far as I understand, we are talking about flux - per area at specified distance, not luminosity. I did recalculate flux for 0.5 m.
- jennyyang 7y agoNo. The study I referenced used total energy per cm^2 required to deactivate the flu virus, which is J/cm^2. You get that by multiplying the flux by the exposure time. So whichever exposure time gets you the 1.8 J/cm^2 is enough to kill the flu virus and presumably SARS-CoV-2.
- blackhaz 7y agoWell, like I said - I recalculated for the flux of the 15 W lamp. An hour of zapping gets you to 1.72 J/cm^2 which is very close to your 1.8 J/cm^2 figure.
- jennyyang 7y agoWe are not disagreeing here, I think your 60 min calculation is correct. My point is that your calculations are at 50 cm and you get a much lower time for exposure if you bring your light bulb much closer and figure out a way to reflect the UV light so that more light from the bulb hits the intended target.