4 ms·
The point is that you need more bits to store a longer key, but the storage space saved is very little in this case compared to how much easier it is to crack.
by joshuaissac 7y ago
The point is that you need more bits to store a longer key, but the storage space saved is very little in this case compared to how much easier it is to crack.
- necovek 7y agoSure, but a difference of 0.1% of storage to go from 80-bit key to 1024-bit key for 1 Megabit of data (that's 118 bytes out of 128KiB), or 0,00001% for 1Gbit (128MiB) seems not worth raising as a concern. (I've chosen example numbers just to make calculation trivial) So I can't ever imagine storage size being the driver for choosing the key size, though from the other threads, it seems that there are algorithms that do have a storage overhead that might be related to key sizes.