2 ms·
Both are possible in Haskell: factorial 0 = 1 factorial n = n * factorial (n - 1) // or: factorial n = case n of 0 -> 1 n -> n * factorial (n
by TazeTSchnitzel 7y ago
Both are possible in Haskell:
factorial 0 = 1
factorial n = n * factorial (n - 1)
// or:
factorial n = case n of
0 -> 1
n -> n * factorial (n - 1)