4 ms·
Let a=12 then (a-2)^2 + (a-1)^2 + a^2 + (a+1)^2 + (a+2)^2 /365 and a binomial a+b squared yields a^2 + 2ab + b^2 so a^2 + 4 + a^2+1 + a^2 +
by CliffStoll 7y ago
Let a=12 then
(a-2)^2 + (a-1)^2 + a^2 + (a+1)^2 + (a+2)^2 /365
and a binomial a+b squared yields a^2 + 2ab + b^2 so
a^2 + 4 + a^2+1 + a^2 + a^2+1 + a^2 + 4
add up all those a^2 's to get
5a^2 + 10
replace a by 12 and
720 + 10
yields 730
Divide by 365
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