3 ms·
Isn't it more accurate to say that isolated entanglement is not stable? Basically any interaction with some other particle causes that particle to become entan
by atq2119 7y ago
Isn't it more accurate to say that isolated entanglement is not stable?
Basically any interaction with some other particle causes that particle to become entangled as well, and so you very easily get "avalanches" of entanglement that spread at the speed of light.
As soon as the avalanches reaches "the observer", the observer themselves become entangled with the originally entangled particle, which means that from their perspective it looks as though they no longer are. This is similar to conditional probabilities.
- K0SM0S 7y agoThe math says so (and the math is right¹), but how we interpret it is another story entirely. To get back on the example of dices: we might be building a whole storytelling around "probabilistic dices" because we haven't formalized the concept of the hand behind, yet. I've always pictured entanglement as totally acceptable if you postulate an extra dimension. Then you simply have to picture a link in that extra dimension between the particles, like a 'U' crossing flatland in two 'dots' (particles) would manifest as 'entanglement' for the flatlanders. But I've really grown skeptical of all such interpretations now (mine very much included), I'd tell you honestly that I probably favor the one that seems most beautiful to me within the space of possibilities (which is what I care about and investigate, the pure science). Interpretation is belief, basically, even if your name is Schrödinger. ____ [1]: Even if eventually found to be partial as the article suggests, I think it's fair to assume any "new" quantum theory would be to QED/QCD what General Relativity was to Newton's equations of motion: precisely a generalization from which to derive Newton for small-ish quantities. Ergo, we can assume QM is 'True'.