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There's the pipe operator in a lot of languages (|>) to try and solve this problem, but it has always felt clunky to me. Compare: f(g(h(x))) x.h.g.f x |> f |

by smabie 7y ago

There's the pipe operator in a lot of languages (|>) to try and solve this problem, but it has always felt clunky to me. Compare: f(g(h(x))) x.h.g.f x |> f |> g |> h I think most people prefer the second one to all the rest.

Udik 7y ago
I think the third example should be: x |> h |> g |> f Which is identical to the second, except for a more eloquent choice of the pipeline symbol?
- whlr 7y ago
  That is the version of the |> operator I'm familiar with from Julia.