4 ms·
I don't think we'd want to put those in our laps if they were dropping that much over linear regulators... Roughly (Dropped Voltage)*(Current through regulator)
by guerrilla 7y ago
I don't think we'd want to put those in our laps if they were dropping that much over linear regulators... Roughly (Dropped Voltage)*(Current through regulator)=(Power Dissipated)