You're multiplying the input by a constant factor. If wear is proportional to (weight per tire)^4, and you've halved weight per tire by having twice as many, yo

You're multiplying the input by a constant factor. If wear is proportional to (weight per tire)^4, and you've halved weight per tire by having twice as many, you've just reduced wear to 6% of its original value. I don't know if doubling tire counts really does this, but it's hard to see why twice as many axles would help but tires per axle would not. It's possible (the pressure underneath the tires is reduced, but the tires exerting pressure on the road are closer together) but counter intuitive to say the least. And there's no proof in this thread that it doesn't help except for masklinn's misinterpretation of the original study.