4 ms·

The square brackets for arithmetic conditionals in bash are deprecated. Rather than: [ $[$RANDOM % 10] = 0 ] ...you can use double-parentheses. Therein, y

The square brackets for arithmetic conditionals in bash are deprecated. Rather than: [ $[$RANDOM % 10] = 0 ] ...you can use double-parentheses. Therein, you can omit the `$` on variables and, remember, the expression evaluates to true for any non-zero value. Thus, instead: (( RANDOM % 10 ))

kd5bjo 7y ago
You changed the probability here from 10% to 90% by inverting the test.
- athorax 7y ago
  True, you can just invert: alias clear='if ! (( RANDOM % 10 )); then timeout 3 cmatrix; clear; else clear; fi'
  - jgtrosh 7y ago
    ((RANDOM % 10)) || timeout 3 cmatrix ; clear
bewuethr 7y ago
$[...] also establishes an arithmetic context, so $[RANDOM % 10] works fine – but you're right, $[...] is not even mentioned in the manual any longer. The release notes[1] say that it's "no longer supported" in the changes for Bash 2.0 (that's 1996!), and Chet Ramey talks about it in the bug-bash mailing list[2]. [1]: http://tiswww.case.edu/php/chet/bash/NEWS http://tiswww.case.edu/php/chet/bash/NEWS [2]: https://lists.gnu.org/archive/html/bug-bash/2012-04/msg00034.html https://lists.gnu.org/archive/html/bug-bash/2012-04/msg00034...
artursapek 7y ago
This perfectly illustrates why I never bothered to learn bash syntax, and always just google for examples.