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Isn't that a fundamental misunderstanding of the definition of "observer" in quantum physics? To "observe" is to cause a quantum system to interact in such a wa
by Causality1 7y ago
Isn't that a fundamental misunderstanding of the definition of "observer" in quantum physics? To "observe" is to cause a quantum system to interact in such a way that collapses probabilities. Whether there is a living observer is totally irrelevant.
- jes5199 7y agoif I remember correctly, this paper specifically tries to prove that those are the same
- v77 7y agoI would say this is considered an open question.
- hprotagonist 7y agoit is “the measurement problem”. https://en.wikipedia.org/wiki/Measurement_problem https://en.wikipedia.org/wiki/Measurement_problem
- scotty79 7y agoOnly for non-physicists and physicists wondering about things outside of physics.
- BalinKing 7y agoAFAIK the details are unknown (e.g. what constitutes the boundary between the “measuring” system and the one that’s being “measured”), but the “alive”-ness of the observer is definitely known to be irrelevant.
- skosch 7y agoUnless ... there is no observer at all: https://en.wikipedia.org/wiki/Superdeterminism https://en.wikipedia.org/wiki/Superdeterminism