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This doesn't actually fork a JVM process, right? It's just splitting up a calculation "unit", which behind the scenes gets mapped to different execution thread
by mbreese 16y ago
This doesn't actually fork a JVM process, right? It's just splitting up a calculation "unit", which behind the scenes gets mapped to different execution threads. Does that sound about right?
- andreaja 16y agoAs I understand it, that is about it. And for that exact reason it bugs me that they call it fork/join.
- iliastsagklis 16y agoYeap, that's exactly it...