4 ms·

Note that they're talking watts not joules. That implies continuous output, or heavy duty-cycle output. At 480V, that's 250 Amps. That's a very heavy-duty curr

Note that they're talking watts not joules. That implies continuous output, or heavy duty-cycle output. At 480V, that's 250 Amps. That's a very heavy-duty current, and necessitates very heavy conductors to reduce the resistance as much as possible. Wouldn't it be better to use a higher voltage and allow for the use of a lower current, and not so massive conductors?

gus_massa 7y ago
There are many models and I'm not an expert so I'm not sure which type they are using. But note that the usual number of kilowatts is for the power during the peak. For example from: https://en.wikipedia.org/wiki/Q-switching#Typical_performance https://en.wikipedia.org/wiki/Q-switching#Typical_performanc... > Typical performance > A typical Q-switched laser (e.g. a Nd:YAG laser) with a resonator length of e.g. 10 cm can produce light pulses of several tens of nanoseconds duration. Even when the average power is well below 1 W, the peak power can be many kilowatts. Large-scale laser systems can produce Q-switched pulses with energies of many joules and peak powers in the gigawatt region. On the other hand, passively Q-switched microchip lasers (with very short resonators) have generated pulses with durations far below one nanosecond and pulse repetition rates from hundreds of hertz to several megahertz (MHz).
anonsivalley652 7y ago
Yep. And it's continuous wave (CW) and 100% duty cycle, if you have a fairly sizable water chilling plant to support it. I don't believe it straight out, but would need to do manufacturing-side due-diligence and see demos (like cutting AR500) to believe it.