> The code you're using to demonstrate the simplicity of char arrays has a buffer overflow vulnerability: what happens when the input int is large? You're provi

> The code you're using to demonstrate the simplicity of char arrays has a buffer overflow vulnerability: what happens when the input int is large? You're proving my point. I did that deliberately to show how tempting, but also dangerous, it is to use char buffers in C. I'm not advocating char buffers. I'm advocating not using C, and not buying arguments of the form "C's fine if you just do this thing that no-one does".