It is definitely not that, since the article shows that a^b = -b^a. I suppose that it's the choice that ij = k as opposed to -k? I'm not sure, but the article'

It is definitely not that, since the article shows that a^b = -b^a. I suppose that it's the choice that ij = k as opposed to -k? I'm not sure, but the article's implication that nobody else cares why things work to be distracting and insulting. > Personally, I have always found it important to actually understand the things I am using.