4 ms·
That's why you use the mean tide which averages over all the possible positions of the sun and the moon, not the momentary tide which, like many computer proble
by fhars 7y ago
That's why you use the mean tide which averages over all the possible positions of the sun and the moon, not the momentary tide which, like many computer problems, depends on the time of the day and the phase of the moon.