7 ms·

Or in functional rust (1..5) .into_iter() .filter(|i| i % 3 == 1) .map(|i| i * i) .sum(); I don't know if we really need a new syntax for ma

• crooked-v 7y ago
  That's also basically the same syntax as doing it in JS, aside from the lack of builtins: import { range } from 'ramda'; range(1, 6) .filter(i => i % 3 === 1) .map(i => i * i) .reduce((a, b) => a + b, 0); Or, if you're using the pipeline operator (experimental, stage 1, nobody can quite decide on exactly the syntax but this gives the rough idea): import { range, sum } from 'ramda'; range(1, 6) |> x => x.filter(i => i % 3 === 1) |> x => x.map(i => i * i) |> sum
  • 1-more 7y ago
    We can get rid of these arrows using ramda's curried list functions, at the expense of being slower and harder to read but making us feel more clever: pipe( range, filter(pipe( modulo(__, 3), // x => x % 3 equals(1) // y => y === 1 )), map(flip(Math.pow)(2)), sum )(1,6)