IFS controls the "$* joining character, if I remember correctly, and so if you use IFS=\0 then you can “safely” pass multiparty args in and then somehow take th

IFS controls the "$* joining character, if I remember correctly, and so if you use IFS=\0 then you can “safely” pass multiparty args in and then somehow take them apart on the other side. But this is the bad kind of crazy to me, and if I was reviewing code with this in it, I’d flag it for replacement. It’s the sort of thing that leads to feeling smart at working around knowing $@ but in the end it’s best just to truly understand $@ or use helper scripts to avoid quoting drama altogether. YMMV.