14 ms·
two pizza team = 8 ICs max reporting every 8 ICs + 1 manager = 9 every 8 managers = 1 director = 8 * 9 + 1 = 73 every 8 directors = 1 sr director = 8 * 73 +
by codemac 7y ago
two pizza team = 8 ICs max reporting
every 8 ICs + 1 manager = 9
every 8 managers = 1 director = 8 * 9 + 1 = 73
every 8 directors = 1 sr director = 8 * 73 + 1= 585
every 8 sr directors = 1 VP = 8 * 585 + 1 = 4681
every 8 VPs = 1 SVP = 8 * 4681 + 1 = 37449
every 8 SVPs = 1 EVP (c level exec) = 8 * 37449 + 1 = 299593
Clearly the problem is one of the large distribution of team sizes, rather than just "have less VPs".
- JMTQp8lwXL 7y agoCertainly an anomaly, but there's a distribution to the number of ICs assigned to the lowest level managers (M1/M2s). I've seen anywhere from 3 to 30. The people with 30 basically just jumped from 1:1 to 1:1 on repeat biweekly.
- username90 7y agoProblem is that there aren't enough people to every VP, so they fight for headcount and projects leading to frequent reorgs or projects shuttering to make room for VP's pet projects.
- thrower123 7y agoIt's interesting how closely these estimates correspond to military TOEs. It's almost like we've figured out over the course of thousands of years what the most effective general-purpose hierarchical organization is.