3 ms·
This doesn't make any sense for multiple reasons, but especially because you wouldn't be checking anything in the first place. A big endian system would would r
by BubRoss 7y ago
This doesn't make any sense for multiple reasons, but especially because you wouldn't be checking anything in the first place. A big endian system would would reorder bytes and a little endian system would just use it directly from memory without another copy or reordering anything.