5 ms·
Java one liner : Stream.iterate(1, i -> i + 1).filter(i -> !IntStream.range(2, i).filter(v -> i % v == 0).findAny().isPresent()).skip(100000).findFirst();
by vincnetas 7y ago
Java one liner :
Stream.iterate(1, i -> i + 1).filter(i -> !IntStream.range(2, i).filter(v -> i % v == 0).findAny().isPresent()).skip(100000).findFirst();