4 ms·
Since each hand beats two other hands, you only need three possible outputs to beat any opposing hand.
by maxander 7y ago
Since each hand beats two other hands, you only need three possible outputs to beat any opposing hand.
- avip 7y agoThe conclusion does not follow... (the missing condition is that every hand is beatable)
- personjerry 7y agoThere are 5 possible hands Each hand beats 2 distinct hands With 3 distinct hands you can cover up to 6 distinct hands which is a superset of all possible hands 3 * 2 > 5
- avip 7y agoAnd yet... A --> D | E B --> D | E C --> D | E D --> C | E E --> D | C QED
- personjerry 7y agoUm, this isn't a general math problem; We're not solving for all possible sets. We're solving this problem in particular: A --> B | C B --> C | D C --> D | E D --> E | A E --> A | B