2 ms·
tan does not have a discontinuity at zero. |x|/x does, as does 1/x. tan's is at pi/2 in particular and (n+1/2)pi in general.
by mjcohen 7y ago
tan does not have a discontinuity at zero. |x|/x does, as does 1/x. tan's is at pi/2 in particular and (n+1/2)pi in general.
- duelingjello 7y agoAlthough tan has a set of discontinuities when it jumps between +∞ and -∞ through complex infinity (∞~). tan(π(x + 0.5)) = ∞~, x ∃ ℤ (π on my screen doesn't look much like greek pi.)