3 ms·
Collisions are expected (fill factors are typically typically 2/3 to 3/4). You make every bucket in the table a linked list. And check each value in the list ag
by cellar_door 7y ago
Collisions are expected (fill factors are typically typically 2/3 to 3/4). You make every bucket in the table a linked list. And check each value in the list against that for which you are searching.
- dplavery92 7y agoThis, I believe, is the exactly the behavior the parent commenting was describing (and bemoaning.) If you you have to check against every term in a linked list (an operation proportional to the length of the list), then your hash table ceases to be constant-time once you get collisions. In that case, if you have a hash table of fixed size, but arbitrarily increase the number of entries in the table, then the look-up time tends as O(n).
- avl999 7y ago> if you have a hash table of fixed size No HashTable implementation worth it's salt is going to have a fixed size table. They are going to dynamically grow the size of the table (double it) once certain level of utilization is reached in the table (say 50%). In practice this means that chains at the same bucket will be of some small constant length assuming a good hash function.
- adrianN 7y agoHash tables with buckets are the simplest implementation, but also the least performant. Cuckoo hashing for example deals with collisions differently.
- loeg 7y agoOr use probing.
- abhishekjha 7y agoJava switches to Red-Black after a bucket's linked list's length has grown upto some constant number(8?).