5 ms·
Information could be encoded in molecule oscillations and therefore 2 rocks of different temperatures would communicate it when touching (heat transfer would oc
by gear54rus 7y ago
Information could be encoded in molecule oscillations and therefore 2 rocks of different temperatures would communicate it when touching (heat transfer would occur). Can this be considered processing?
- cygx 7y agoIt's doubtful you'll be able to make such a scheme work: Information processing tends to involve storage and retrieval of data. That's not really possible in the thermodynamic regime. You'd have to do all your processing before the information gets lost to thermalization.
- ghjyui 7y agoImage recognition needs no storage or retrieval of data: it's a single pass thru a series of matrix multiplications. Yet, image recognition is the very definition of data processing.
- cygx 7y agoHow do you propose to perform calculations without data storage (think registers)?
- adrianN 7y agoLike this for example https://hackaday.com/2019/07/16/neural-network-in-glass-requires-no-power-recognizes-numbers/ https://hackaday.com/2019/07/16/neural-network-in-glass-requ... though I'm not sure that you can really count this as calculation. But I guess that's the point of this discussion.
- hackinthebochs 7y agoHeat is entropy, but entropy is basically a measure of disorder/randomness. So when two substances transfer heat, they necessarily are not communicating information, except perhaps that there exists a temperature differential.