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Modern C++, since there is no 'runtime' (and don't say linked in functions are a 'runtime'). If you have an example of where you think this breaks down I'll be
by BubRoss 7y ago
Modern C++, since there is no 'runtime' (and don't say linked in functions are a 'runtime'). If you have an example of where you think this breaks down I'll be happy to come up with a solution.
- jchw 7y agoSo when you throw an exception in C++, and the stack is being unwound, it is not being unwound by your C++ runtime? And the C++ standard library, specified in the same standard as the language, that you have, that has code present at runtime, is not part of the runtime? Someone should let Microsoft know they need to rename their “C++ Runtime Library” package.
- Const-me 7y agoThey all optional. Don't throw exceptions and they won't unwind. Standard library is optional, there're good alternatives like ATL and EASTL. Microsoft's package is optional, change a compiler switch and your binary will stop using or requiring that package. However, manual memory management makes development more expensive. Especially if you don't crunch numbers but parse strings. C++ probably ain't a good replacement for Go. For the last decades people and whole industries have been migrating the other way, from C++ to higher level memory safe languages, initially Java and C# then others followed.
- jchw 7y agoSigh. I avoided mentioning that the C++ runtime was optional because I was trying not to be pedantic and I assumed in context it would be understood that this was irrelevant. I think I should’ve just made my point earlier, but: - This all started with someone mentioning that C++ doesn’t have ‘bad runtime behavior’ because it doesn’t have a runtime, but this is false. It has a runtime, or to be exact, a specification for one, and I think it is safe to say a vast, perhaps extreme, majority of C++ developers are using it. - If you opt to not use the runtime, then your runtime behavior is dictated somewhere else, but runtime behaviors don’t go away. In freestanding, you may be your own runtime, but then your runtime behavior is defined by the machine you’re running on. You just get to choose what layer of abstraction you are sitting on. - edit: And also, as a point I forgot to mention initially, I don’t really feel like freestanding C++ vs standard Go is an apples-to-apples comparison. I think the point was that the C++ has less runtime behavior, since it doesn’t have a scheduler or garbage collector, but extrapolating that to no runtime is wrong even if the runtime is optional.
- Const-me 7y agoAs far as I understood the context, it was about language runtimes. Underneath all languages, there’re usually OS kernel, drivers and hardware. They all have non-trivial amount of unexpected behavior, especially under load. But these apply to code written in all languages, almost equally. BTW, C++ does have a scheduler. Optional like the rest of the runtime, but it’s 1 line of code away in all modern compilers, that line starts with #pragma omp.
- jchw 7y agoYes, that seems about right. There’s always behavior at runtime, and your language shields it away from you to varying degrees. It is the same for all languages, which is exactly what I am trying to drive home. However, even if you go to the extreme of not using any features that require runtime support, if you are using hosted C++, in practice you still have one bit of runtime: the entrypoint. Technically, an operating system could implement the bits that call main, but to the best of my knowledge none of them ever have. So every compiled binary from every hosted C++ implementation begins at the runtime library. (Admittedly, normally the C runtime library, since C++ doesn’t differ here, but that is just another layer deep of pedantics. In practice, everyone has a runtime.) Nitpick: As far as I am aware OpenMP is not part of the language itself but an extension. But yeah, you could argue that is runtime scheduling in C++, I think.
- saagarjha 7y agoIf you don’t have static initalizers you should just be able to set your entrypoint to be main, no?
- jchw 7y agoNot really, because the entrypoint of executables is OS dependent and may not resemble the “main” function signature. I actually don’t know what Linux dumps on the stack/registers before calling your entrypoint, though, to be honest.
- Gupie 7y agoThere is heap defragmentation.