Given 11 numbers: n, n+1,...,n+10 the sum of 10 of them: 10*n+sum_conseq=2012 where max(sum_conseq)=0+1+...+10=(0+10)+(1+9)+(2+8)..=55 therefore erased

Given 11 numbers: n, n+1,...,n+10 the sum of 10 of them: 10*n+sum_conseq=2012 where max(sum_conseq)=0+1+...+10=(0+10)+(1+9)+(2+8)..=55 therefore erased number is n+3 because (2012-55-3) divisible by 10 -> n=196.