3 ms·

Ignoring zero, I get the summation, starting at [1]=2, of {1,3,1,1,1,3,3,3,1,1,1,1,1,1,1,1,1,3,...} = {..{1}^3^i,..{3}^3^i for i in ℕ} Edit: derp, it's ℕ, not

by a1369209993 7y ago

Ignoring zero, I get the summation, starting at [1]=2, of {1,3,1,1,1,3,3,3,1,1,1,1,1,1,1,1,1,3,...} = {..{1}^3^i,..{3}^3^i for i in ℕ} Edit: derp, it's ℕ, not ℤ⁺.