3 ms·
Yes, it's done all the time. Suppose you have a model A that predicts some value for input x and you also have model B for the same problem, and they both work,
by toolslive 7y ago
Yes, it's done all the time. Suppose you have a model A that predicts some value for input x and you also have model B for the same problem, and they both work, but are not optimal for all cases, so they do the following:
C(x) = alfa * A(x) + (1-alfa) * B(x)
tada.
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