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The second problem seems open-ended and a test of UX/creativity skills: "There is no objectively 'right' answer here, and in fact there may be multiple ways to
by mayank 16y ago
The second problem seems open-ended and a test of UX/creativity skills: "There is no objectively 'right' answer here, and in fact there may be multiple ways to interpret a provided list of file events."
The third problem is not zero-sum, it's subset-sum: http://en.wikipedia.org/wiki/Subset_sum http://en.wikipedia.org/wiki/Subset_sum
I never understood the value of these simplified competitions. If your goal is to test implementations of approximation algorithms, then at least make the conditions realistic, like the Netflix prize.
- benmathes 16y agoThese simplified competitions seem to filter for applicants who can recognize the canonical problems like knapsack/zero-sum/etc. and then successfully implement them.
- Andys 16y agoWhile you might think of these sorts of problems as simplified, they really do work well to filter out the sort of programmers you definitely don't want to hire. And for many programmers you might want, its a simple enough problem that it isn't very time-consuming for them.
- tel 16y agoI think the Netflix prize is a pretty bad comparison since it fueled years of active research from top machine learning and data mining people. It's great work, but if you're trying to find new hires the time scale is quite a ways off.
- mayank 16y agoOn the contrary, within a few days of the Netflix prize challenge being launched, a guy put up a detailed blog post with a simple linear algebra method that could beat Netflix's system at the time (link below). It didn't come anywhere near the 10% improvement threshold, but it beat Netflix's system with a handful of lines of C code, and it ran off his laptop. Sounds like he would have made an excellent hire. http://sifter.org/~simon/journal/20061211.html http://sifter.org/~simon/journal/20061211.html
- tel 16y agoHaha, I stand very well corrected!
- GoogleMeElmo 16y ago>"The third problem is not zero-sum, it's subset-sum: http://en.wikipedia.org/wiki/Subset_sum http://en.wikipedia.org/wiki/Subset_sum That is correct. I have messed the names up :P