No, the ordering of the eigenvalues of M doesn't matter, because we take their product (or rather, the product of their difference from a fixed number), and mul

No, the ordering of the eigenvalues of M doesn't matter, because we take their product (or rather, the product of their difference from a fixed number), and multiplication commutes. It's maybe not obvious, and as such I can understand auggierose's complaint to an extent, though it was maybe unnecessarily harshly phrased.