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I'm a physicist and I hate to say that I'm stuck on the first equation in the first lemma. Can anybody clarify what the following notation means? \det(B\qu
by leni536 7y ago
I'm a physicist and I hate to say that I'm stuck on the first equation in the first lemma. Can anybody clarify what the following notation means?
\det(B\quad v_n)
For the determinant to make sense its argument needs to be an m×m matrix. B is an n×(n-1) matrix, v_n is an n dimensional vector.
- dschooh 7y agoAs you are saying, B misses a column to be square. That column is filled with v_n. B and v_n are simply concatenated.
- Recursing 7y agoThe blog post https://terrytao.wordpress.com/2019/08/13/eigenvectors-from-eigenvalues/ https://terrytao.wordpress.com/2019/08/13/eigenvectors-from-... is very readable and interesting There's a comment with your exact question and the answer "It’s not multiplication, it’s concatenation: stick the column vector after the last column of B to “complete the square”."