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>An even stronger example of this is the fact that due to the way Haskell arrows work, all Haskell Functors are actually "strong" functors in the sense that we
by crimsonalucard 7y ago
>An even stronger example of this is the fact that due to the way Haskell arrows work, all Haskell Functors are actually "strong" functors in the sense that we cannot even truly specify a non-string functor.
Can you explain this? What is a strong functor and how does it have to do with arrows? Also what do you mean by non-string functor?
- tel 7y agoA strong functor is one which supports the strength operation above. Haskell -> arrows being based on any lambda term are rich enough to make all Haskell functors strong. But not all functors are! And “non-string” was just a typo.