3 ms·
My guess is that as long as the orbital periods of the involved planets are sufficiently different (not being rational multiples of each other for example) , ma
by ravar 7y ago
My guess is that as long as the orbital periods of the involved planets are sufficiently different (not being rational multiples of each other for example) , making the system ergodic . Then Mercury will always be the closest by the metric.
- gus_massa 7y agoSomewhat related: The three inner Galilean moons of Jupiter are in a 1:2:4 resonance https://en.wikipedia.org/wiki/Galilean_moons#Orbit_animation https://en.wikipedia.org/wiki/Galilean_moons#Orbit_animation https://xkcd.com/1300/ https://xkcd.com/1300/ Also, the ex-planet Pluto is in a 2:3 resonance with Neptune. https://en.wikipedia.org/wiki/Resonant_trans-Neptunian_object https://en.wikipedia.org/wiki/Resonant_trans-Neptunian_objec...