4 ms·
Right. But the difference is modifying any memory under GDB will be seen by the process. It's not copy-on-write
by aloknnikhil 7y ago
Right. But the difference is modifying any memory under GDB will be seen by the process. It's not copy-on-write
- coldtea 7y agoIsn't that a feature for debugging tho?
- aloknnikhil 7y agoAbsolutely. I was arguing for "unforking" to say a patched version of the process and verifying a fix without actually modifying the live process.