3 ms·
The way TREE grows it's very much possible that all these are inferior to simply f(n) = TREE(n+1).
by contravariant 7y ago
The way TREE grows it's very much possible that all these are inferior to simply f(n) = TREE(n+1).
- x3n0ph3n3 7y agoUnlikely since we are piping the output of TREE back into TREE, which is much larger than n+1.