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To be fair, it looks like what he's proposing is fundamentally different from inertial confinement fusion. Inertial confinement with lasers is so hard because i
by cbkeller 7y ago
To be fair, it looks like what he's proposing is fundamentally different from inertial confinement fusion. Inertial confinement with lasers is so hard because it's so tricky to apply perfectly even, symmetric force on every side of the hohlraum. What's being proposed here seems to be more on the line of <attosecond laser pulses directly exciting the nucleus, so wouldn't be useful for fusion but would have very different yields and wouldn't have the same trouble with maintaining confinement.
- petschge 7y agoMaybe. It is hard to find any scientifically accurate information on his proposal. But if you say he wants laser intensities that are directly sufficient to get 1 MeV (typical nuclear energies) across the 10fm of a nucleus he would need intensities that are about a factor 100 above the Schwinger limit [1] where the laser simply produces electrons and positrons out of the vacuum. Cool if you want to study the plasma environments of pulsars, but probably a HUGE loss mechanism in getting energy into the nucleus. In the end it all boils down to the fact that visible light an laser operate on the energy scale of electronic transitions whereas nuclear transmutations occur at the vastly different energy scale of the strong force. This huge separation between electromagnetic interactions and strong nuclear interactions is btw also the reason why radioactive material is not typically green glowing goo. 1: https://en.wikipedia.org/wiki/Schwinger_limit https://en.wikipedia.org/wiki/Schwinger_limit
- sansnomme 7y agoSwinger?
- deleted 7y ago[deleted]
- petschge 7y agoSorry, that was a horrible typo for "Schwinger limit" that is now fixed. An explanation can be found at [1]. The limit comes from the following process: Thanks to quantum mechanics there is an uncertainty principle between position and momentum. Less known it the uncertainty between time and energy. (If you have studied classical mechanic you will recognize that the variable pairs are the same that you know from Noethers theorem [3].)This implies that nature can (and will) violate conservation of energy by an amount deltaE for a time deltat up to hbar/deltaE. One such process is the creation of a electron-positron pair out of vacuum. That violates energy conservation by about 1 MeV and you have to return the (virtual) particles within hbar/1MeV or approximately 6e-22 seconds. If however the electric field is sufficiently large that the particles get accelerated to an energy of 1 MeV within that time they get to stay. An electric field that can do that has a field strength of 1.3e18 V/m. At that intensity the laser light does not simply propagate through vaccuum as predicted by Maxwells equations, but is producing a pair plasma and gets damped. The process is fairly well described by QED. We are currently trying to get laser up to that intensity and to make accurate measurements of this QED effect as it does not only work for electron-positron pairs, but arbitrary particle-antiparticle pairs. Experimental deviations from the QED predictions would therefore imply the existence of additional light particles (and antiparticle) that we have not found through other methods. 1: https://en.wikipedia.org/wiki/Schwinger_limit https://en.wikipedia.org/wiki/Schwinger_limit 2: https://en.wikipedia.org/wiki/Uncertainty_principle https://en.wikipedia.org/wiki/Uncertainty_principle 3: https://en.wikipedia.org/wiki/Noether%27s_theorem https://en.wikipedia.org/wiki/Noether%27s_theorem
- cbkeller 7y agoTotally. As Mourou puts it in the talk, "we are boiling the vacuum!" Going of the figures in the talk, it looks like he would be counting on ultrashort pulses that are well into the realm of relativistic optics, and possibly approaching the QCD regime.
- ClumsyPilot 7y agoI feel you are looking on the wrong numbers. Yes, individual photons are hugely more energetic, and the process is lossy, but it does not mean the process will consume a lot of energy - very few might be needed. You previous calculations are for creating light pressure sufficient for fusion, that's a uniquely energy consuming process, You can't reuse those numbers here because they are not trying to crush Uranium atoms together. But likewise I could not find concrete details for the proposal.