> What am I missing here? I am unsure what you are missing because what you explained is approximately correct. Minor correction: Entangled qubits (each of 5

> What am I missing here? I am unsure what you are missing because what you explained is approximately correct. Minor correction: Entangled qubits (each of 50% propbaility to be up) can have more possible measurement distributions that the two you mentioned. Distributions like the following exist. +/+ 20% +/- 30% -/+ 30% -/- 20% > if I have several pairs of entangled electrons all with spin of 50% up / 50% down, then I might expect the results of measuring the spin of those pairs to look something like this table: I think you may misunderstand how to get qubits entangled. You would have to pass two qubits through a two-qubit gate to get them entangled. And doing so would leave you with only one measurement distribution. For example if you have a qubit in 50% |1>, 50% |0> and pass it through CNOT with a qubit in |1>. You get: |11> 0 |10> 50% |01> 50% |00> 0 But if the second qubit was in state |0>, you get |11> 50% |10> 0 |01> 0 |00> 50% > if I have several pairs of entangled electrons all with spin of 50% up / 50% down Also just in case you don't know qubits have phase so there is more than one way to have a qubit that when measured will be up 50% of the time.