4 ms·
> Can someone explain why ∇Θ is only applied to the first term? It's not, there's an implied parenthesis: (∇_Θ)J = (∇_Θ)( yTy − (XΘ)Ty − yTXΘ + ΘT(XTX)Θ ). I
by Myrmornis 7y ago
> Can someone explain why ∇Θ is only applied to the first term?
It's not, there's an implied parenthesis:
(∇_Θ)J = (∇_Θ)( yTy − (XΘ)Ty − yTXΘ + ΘT(XTX)Θ ).
In the subsequent expressions you can see derivatives being taken of all the terms.